36x^2-4x-7=0

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Solution for 36x^2-4x-7=0 equation:



36x^2-4x-7=0
a = 36; b = -4; c = -7;
Δ = b2-4ac
Δ = -42-4·36·(-7)
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-32}{2*36}=\frac{-28}{72} =-7/18 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+32}{2*36}=\frac{36}{72} =1/2 $

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